BOJ 1849 : 순열

• 문제 링크 : boj.kr/1849
• 난이도 : P5
• 태그 : 세그먼트 트리, 이분 탐색

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코드

#include <bits/stdc++.h>

#define all(x) (x).begin(), (x).end()

#define INF 0x7FFFFFFF

using namespace std;

using ll = long long;
using ld = long double;
using pii = pair<int,int>;
using pll = pair<ll, ll>;

template<typename T>
class segTree {
private:
    ll n;
    T id;
    T(*merge)(T, T);
    vector<T> tree;
public:
    segTree(ll n, T id, T(*merge)(T, T)) {
        this->n = n;
        this->id = id;
        this->merge = merge;
        tree.resize(n*4);
    }
    void update(ll idx, T value) {
        _update(1, 1, n, idx, value);
    }
    T query(ll l, ll r) {
        return _query(1, 1, n, l, r);
    }
private:
    void _update(int node, int s, int e, int idx, T value) {
        if(idx < s || e < idx) return;

        if(s == e) {
            tree[node] = value;
            return;
        }

        _update(node*2, s, (s+e)/2, idx, value);
        _update(node*2+1, (s+e)/2+1, e, idx, value);
        tree[node] = merge(tree[node*2], tree[node*2+1]);
    }
    T _query(int node, int s, int e, int l, int r) {
        if(l > e || r < s) return id;
        if(l <= s && e <= r) return tree[node];

        T lq = _query(node*2, s, (s+e)/2, l, r);
        T rq = _query(node*2+1, (s+e)/2+1, e, l, r);
        return merge(lq, rq);
    }
};

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);

    int n;
    cin >> n;

    segTree<int> s(n, 0, [](int a, int b){return a+b;});

    vector<int> ans(n+1);
    for(int i = 1; i <= n; i++) {
        int input;
        cin >> input;
        int lo = 0, hi = n+1;
        while(lo < hi) {
            int mid = (lo + hi) / 2 + 1;
            if(mid - s.query(1, mid) <= input) lo = mid;
            else hi = mid-1;
        }
        ans[lo+1] = i;
        s.update(lo+1, 1);
    }
    for(int i = 1; i <= n; i++) cout << ans[i] << "\n";

    return 0;
}

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풀이

#1777과 비슷하게 풀면 된다.