PS
BOJ 9426 : 중앙값 측정
lickelon
2024. 9. 9. 20:11
- 문제 링크 : boj.kr/9426
- 난이도 : P5
- 태그 : 세그먼트 트리
코드
#include <bits/stdc++.h>
#define all(x) (x).begin(), (x).end()
#define INF 0x7FFFFFFF
using namespace std;
using ll = long long;
using ld = long double;
using pii = pair<int,int>;
using pll = pair<ll, ll>;
template<typename T>
class segTree {
private:
ll n;
T id;
T(*merge)(T, T);
vector<T> tree;
public:
segTree(ll n, T id, T(*merge)(T, T)) {
this->n = n;
this->id = id;
this->merge = merge;
tree.resize(n*4);
}
void update(ll idx, T value) {
_update(1, 1, n, idx, value);
}
T query(ll l, ll r) {
return _query(1, 1, n, l, r);
}
private:
void _update(int node, int s, int e, int idx, T value) {
if(idx < s || e < idx) return;
if(s == e) {
tree[node] = value;
return;
}
_update(node*2, s, (s+e)/2, idx, value);
_update(node*2+1, (s+e)/2+1, e, idx, value);
tree[node] = merge(tree[node*2], tree[node*2+1]);
}
T _query(int node, int s, int e, int l, int r) {
if(l > e || r < s) return id;
if(l <= s && e <= r) return tree[node];
T lq = _query(node*2, s, (s+e)/2, l, r);
T rq = _query(node*2+1, (s+e)/2+1, e, l, r);
return merge(lq, rq);
}
};
int main()
{
ios::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int n, k;
cin >> n >> k;
segTree<int> s(65536, 0, [](int a, int b){return a + b;});
ll sum = 0;
vector<int> arr(n+1);
for(int i = 1; i <= n; i++) {
cin >> arr[i]; arr[i] += 1;
s.update(arr[i], s.query(arr[i], arr[i])+1);
if(i < k) continue;
s.update(arr[i-k], s.query(arr[i-k], arr[i-k])-1);
int lo = 0, hi = 65537;
while(lo < hi) {
int mid = (lo+hi)/2;
if(s.query(1, mid) < (k+1)/2) lo = mid+1;
else hi = mid;
}
sum += lo - 1;
}
cout << sum;
return 0;
}
풀이
#1572와 같은 문제이다.
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